(1)丁龍引力:
g = mg = 9.9×10 3kg×10N/kg = 9.9×10 4N,
丁龍壓在臺座上:
F=G=9.9×10 4 N,
丁龍對基座的壓力為:P = F S = 9.9×1.04n 0.9 m2 = 1.1×1.05 pa;
(3)h=2m,
∴起重機所做的功是:
w = G
(1)丁龍引力:
g = mg = 9.9×10 3kg×10N/kg = 9.9×10 4N,
丁龍壓在臺座上:
F=G=9.9×10 4 N,
丁龍對基座的壓力為:P = F S = 9.9×1.04n 0.9 m2 = 1.1×1.05 pa;
(3)h=2m,
∴起重機所做的功是:
w = Gh = 9.9×104n×2m = 1.98×105j。
所以,答案是:1.1×105;1.98×10 5 .